Respuesta :
Answer:
0.625
Explanation:
The slope (m) of a linear regression line is ...
[tex]m=r_{xy}\cdot\dfrac{s_y}{s_x}[/tex]
Then we have ...
[tex]2.5=r_{xy}\cdot\dfrac{4}{1}\\\\\dfrac{2.5}{4}=r_{xy}=0.625[/tex]
The value of the correlation coefficient is 0.625.
Here, we are required to find the value of the correlation coefficient given the slope of the regression model and the standard deviation of the dependent and independent variables.
The value of the correlation coefficient is 0.625
and it is dimensionless.
The relationship between the slope of a regression model and the correlation coefficient is given by;
m = r (Sy/Sx)
where
- m= slope of the regression model = 2.5cm/pH.
- r = the correlation coefficient = ?
- Sy = The standard deviation of the dependent variable i.e Plant height = 4cm
- Sx = The standard deviation of the independent variable i.e soil acidity(pH level) = 1pH
Therefore;
2.5 = r × (4/1)
r = 2.5/4
r = 0.625
P.S: It is important to know that the correlation coefficient is a dimensionless parameter.
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