Question

Find the perimeter of the shape given length = x^2+4 and the width = 3x-4.Explain how you found your answer to problem .

Answer 1

Answer:

$2x^{2}+6x$

Step-by-step explanation:

Perimeter is the distance all round a figure. Given length and width only, then this shale is likely to be a triangle. For a triangle, the area is given by

P=2(l+w)

Where l is the length and w is width.

Substituting w with 3x-4 and l with $x^{2}+4$

then

$P=2( x^{2}+4 +3x-4)=2( x^{2}+3x)=2x^{2}+6x$

Therefore, perimeter is $2x^{2}+6x$