Respuesta :
Answer:
Approximately, 190.
Explanation:
cross between true breeding stock. let R represent the colour and Y represent the position of flower.
parents RRYY x rryy
F1 gen. RrYy
RrYy x RrYy
F2 gen RY Ry rY ry
RY RYRY RYRy RYrY RYry
Ry RYRy RyRy RyrY Ryry
rY RYrY RyrY rYrY rYry
ry RYry Ryry ryrY ryry
number of red and axial flowers (RY__) - 9
number of red and terminal flowers (Ry_y) - 3
number of white and axial flowers (rYr_) - 3
number of white and terminal flowers (ryry) - 1
We are expected to find the number of red and terminal flowers out of 1,000 F2 offspring. Thus, we have 3/16 x 1000 = approximately 190
The number of the F2 generation that is expected to have red,terminal flowers is ( A ) ≈ 190
Given data :
One parent has red axial flowers = RY
One parent has white, terminal flowers = ry
where : Y = axial R = red color
y = terminal r = white
Note : First generation ( F1 ) all have red, axial flowers ( i.e. RrYy )
Determine the number of the F2 generation that has red,terminal flowers
F2 generation will be :
RrYy * RrYy ( crossing of F1 generation )
RY Ry rY ry
RY RYRY RYRy RYrY RYry
Ry RYRy RyRy RyrY Ryry
rY RYrY RyrY rYrY rYry
ry RYry Ryry ryrY ryry
From the Punnett square table above the number of F2 generation that has Red terminal flowers ( i.e. Ry-y ) = 3. Total outcome from the Punnett square table = 16.
F2 population = 1000
Therefore the number of the F2 generation that has red terminal flowers is = 3 / 16 * 1000
= 187.5 ≈ 190
Hence we can conclude that The number of the F2 generation that is expected to have red,terminal flowers is ≈ 190.
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