Question

By accident, 6 burned out bulbs have additionally been mixed in with 26 good ones. Ken is replacing
old bulbs in his house. If he selects two bulbs at random from the box of 32, what is the probability
they both work?

Answer 1

Answer:

66%

Step-by-step explanation:

first find the probability of finding 1 good lightbulb so that 26/32. next if you happen to find a good lightbulb there is only 31 left if in that exact order so it goes down to 25/31 to find the second bulb. finally you multiply both probabilities, divide the numerator by the denominator to get your percentage in decimal form.

Answer 2

The probability of randomly selecting two good bulbs is equal to 0.665.

How to find the probability?

So, we have a set of 32 bulbs, such that 26 are good and 6 are burned.

The probability of randomly selecting one good bulb is equal to the quotient between the number of good bulbs and the total number of bulbs.

It gives:

P = 26/32

Now, for the next bulb, the probability is computed in the same way, but now there are 25 good bulbs and 31 in total, so the probability is:

P' = 25/31

The joint probability is given by the product between the two individual probabilities:

p = (26/32)*(25/31) = 0.655

If you want to learn more about probability:

https://brainly.com/question/25870256

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