Question

Person a pushes a box on wheeled to the left with a force of 10,000 Newton's .Person b and friction from the floor exerts a net force of 9,990n force to the right how does the box move and why

Answer 1

The box will be pushed by Person A and so the box will move with magnitude of 10 N force and in left direction.

Explanation:

So in the present problem, three forces are acting on the box. The force exerted by Person A on the box is represented as F₁ and it is given as 10000 N. Similarly, the net force exerted by Person B and friction on the box is given as 9990 N and it is represented as F₂. Since, F₁ is acting toward left side and F₂ is acting toward right side, both the force will be acting opposite to each other. Then the net force of all the three force acting on it will be the difference between F₁ and F₂ and the box will move towards the direction of maximum force.

$Net force = 10000-9990 = 10 N$

Thus, the magnitude of the net force acting on the box will be 10 N and as the force exerted by Person A on the box is greater than the combined force of Person B and friction, the box will move towards left side as exerted by Person A.

So the box will be pushed by Person A and so the box will move with magnitude of 10 N force and in left direction.