Answer:
a. n=4148
b. n=3909
c. The sample size is smaller if a known proportion from prior study is used. The difference in sample sizes is 239
Step-by-step explanation:
a. For sample where no preliminary estimate is given, the minimum sample size is calculated using the formula:
[tex]n=p(1-p)(\frac{z}{ME})^2[/tex]
Where:
#Let p=0.5, substitute in the formula to solve for n:
[tex]n=0.5(1-0.5)\times (2.576/0.02)^2\\\\=4147.36\approx 4148[/tex]
Hence, the minimum sample size is 4148
b. If given a preliminary estimate p=0.38, we use the same formula but substitute p with the given value:
[tex]n=p(1-p)(z/ME)^2\\\\=0.38(1-0.38)(2.576/0.02)^2\\\\=3908.47\approx3909[/tex]
Hence, the minimum sample size is 3909
c. Comparing the sample sizes from a and b:
[tex]n_{0.5}>n_{0.38}\\\\n_{0.5}-n_{0.38}=4148-3909=239[/tex]
Hence, the actual sample size is smaller for a known proportion from prior a prior study.