Question

Determine the mass of silver (Ag) produced in the reaction if 6.50X1023 atoms
of magnesium (Mg) react.
2 AgNO3 (s) + 1 Mg(s) 3 Mg(NO3)2 (s) + 2 Ag (s)


How many Grams??

Answer 1

9.49 grams of Ag is produced in the reaction if 6.50X1023 atoms

of magnesium (Mg) react.

Explanation:

Balanced chemical reaction:

2 AgNO3 (s) + 1 Mg(s) 3 Mg(NO3)2 (s) + 2 Ag (s

data given:

6.50X1023 atoms  of magnesium (Mg) react.

then amount of Ag formed =?

We know that 6.022 x $10^{23}$ atoms are present in 1 gram/ mole of  a substance

so 6.50X1023 will have x grams

so, 1.07 grams of Mg will react to form x grams of Ag

atomic mass of Mg 24.30

number of moles of Mg = $\frac{1.07}{24.30}$

                                        = 0.044 moles of Mg

1 mole of Mg reacts to give 2 moles of Ag

0.044 moles of Mg reacts to give x moles of Ag

$\frac{2}{1}$ = $\frac{x}{0.044}$

x = 0.088 moles of Ag is formed  (atomic mass of silver 107.86g/mole)

mass = atomic mass X number of moles

          = 107.86 x 0.088

            = 9.49 grams of Ag is formed.