Answer:
- Every year, the bear population shrinks by a factor of 2/3 .
Explanation:
The concrete question and the function or data were omitted.
I found the complete question on the internet. Please, find attached the picture with the complete question
You must complete the sentence about the yearly rate of change of the bear population, telling whether it grows or shrinks and by what factor.
Thus, the goal is to interpret the rate of change in an exponential model.
The exponential model is:
[tex]N(t)=2187\cdot \bigg(\dfrac{2}{3}\bigg)^t[/tex]
Let's analyze that function.
When t = 0, (2/3)⁰ = 1 and N(0) = 2,187 × 1 = 2,187
Thus, the population of bears starts with 2,187 individuals.
For t = 1, the population will be N(1) = 2,187 × (2/3).
For t = 2, the population will be N(2) = 2,187 × (2/3)²
And so on, every year the population of bears is multiplied by a factor of 2/3.
Since, 2/3 is less than 1, every year the population will be decreasing (decaying), by a factor of 2/3.
Thus, the answer, i.e. the complete sentence, is:
Every year, the bear population shrinks by a factor of 2/3 .
