The slant height of the cone is 39.7 cm
Explanation:
Given:
Lateral surface area of a cone = 558π cm²
Radius, r = 31 cm
Slant height, l = ?
We know:
[tex]A = \pi r\sqrt{h^2+r^2}[/tex]
Where,
h is the height of the cone
r is the radius
Solving the equation further:
[tex]558\pi = \pi r\sqrt{h^2+r^2} \\\\558 = 31\sqrt{h^2+(31)^2} \\\\(18)^2 = h^2 + 961\\\\324 = h^2+ 961\\\\h = 25.23[/tex]
Lateral height, H = ?
Applying pythagoras theorm,
(H)² = (h)² + (r)²
(H)² = (25.23)² + (31)²
(H)² = 636.55 + 961
(H)² = 1597.55
H = 39.7 cm
Therefore, the slant height of the cone is 39.7 cm