Answer:
258 Hz or 266 Hz
Explanation:
When two sounds of similar frequency occur at the same time, a phenomenon called "beat" occurs. The beat is an interference patter between the two sounds; the frequency of this beats (called beat frequency) is given by the difference between the frequencies of the two sounds:
[tex]f_B = |f_1 -f_2|[/tex]
where
[tex]f_B[/tex] is the beat frequency
[tex]f_1[/tex] is the frequency of the 1st sound
[tex]f_2[/tex] is the frequency of the 2nd sound
In this problem,
[tex]f_B=4 Hz[/tex] is the beat frequency
[tex]f_1=262 Hz[/tex] is the frequency of the middle C tuning fork
[tex]f_2[/tex] is the frequency of the middle C piano string
Solving for f2, we find two solutions:
[tex]f_2=f_1-f_B = 262-4 = 258 Hz\\f_2 = f_1+f_B = 262+4=266 Hz[/tex]