Answer:
- The price of a soccer ball is $14.5
- The price of a soccer bag is $5
Step-by-step explanation:
To solve this problem, we call:
s = the price of a single soccer ball
b = the price of a soccer bag
We have:
1) A soccer coach purchases 10 soccer balls and 2 soccers bags for $155: so we can write
[tex]10s+2b=155[/tex] (1)
2) Another scorer coach purchases 12 soccer balls and 3 soccer bags for $189: so we can write
[tex]12s+3b=189[/tex] (2)
So we have a system of two equations in two unknown variables:
[tex]10s+2b=155\\12s+3b=189[/tex]
We solve it by multiplying eq.(1) by 3 and eq(2) by 2, and we get:
[tex]30s+6b=465\\24s+6b=378[/tex]
Now we substract eq(2) from eq(1) and we get:
[tex]6s=87[/tex]
So
[tex]s=\frac{87}{6}=14.5[/tex]
And by using eq(1) we also find the value of b:
[tex]10s+2b=155\\b=\frac{155-10s}{2}=\frac{155-10(14.5)}{2}=5[/tex]
So:
- The price of a soccer ball is $14.5
- The price of a soccer bag is $5