Respuesta :
3.41 is the pH value of a sample that has ten times fewer hydronium ions than an equal volume of a vinegar sample with a pH value of 2.4.
Explanation:
pH of the first sample of acetic acid = 2.4
to know the [H+] concentration in the acetic acid solution, the equation used is:
pH = -log [H+]
[H+] = [tex]10^{-pH}[/tex]
[H+] = [tex]10^{-2.4}[/tex]
[H+] = 3.98 X [tex]10^{-3}[/tex] M
The concentration of H+ ion in first case is 3.98 X [tex]10^{-3}[/tex] M, the second sample has ten times less hydronium ion so concentration of first case is divided by 10.
3.98 x [tex]10^{-4}[/tex] M
Now pH of the sample having 10 times fewer ions of acetic acid:
pH = -log [H+]
putting the values in the above equation:
pH = -log [3.98 x [tex]10^{-4}[/tex] M]
pH = 3.41
If solution has ten times less hydronium ion the pH will change to 3.41.
3.41 is the pH value of a sample that has ten times fewer hydronium ions. pH gives the concentration of Hydronium ion.
What information we have:
pH of the first sample of acetic acid = 2.4
Calculation for [H+] concentration:
To know the [H+] concentration in the acetic acid solution, the equation used is:
[tex]pH = -log [H^+]\\\\H^+ = 10^{-pH}\\\\H^+ = 10^{-2.4}\\\\H^+ = 3.98 *10^{-4} M[/tex]
The concentration of H+ ion in first case is [tex]3.98 *10^{-4} M[/tex], the second sample has ten times less hydronium ion so the concentration of first case is divided by 10.
[tex]3.98 *10^{-4} M[/tex],
Now pH of the sample having 10 times fewer ions of acetic acid:
pH = -log [H+]
pH = -log [ [tex]3.98 *10^{-4} M[/tex],]
pH = 3.41
If the solution has ten times less hydronium ion the pH will change to 3.41.
Find more information about pH here:
brainly.com/question/13557815
