Question

In a calorimeter, the temperature of 100g of water decreased by 10 degrees Celsius when 10g of ice melted. How much heat was absorbed by the ice?

Answer 1

so use equation: ΔH = MCΔT

M = mass of water
C = waters specific heat capacity (4.18)
ΔT = the temp. change of the reaction

ΔH = 100 x 4.18 x 10 = 4180J or 41.8KJ

so the cube absorbed 4180J of energy 

hope that helps 

Answer 2

Amount of heat absorbed by ice cube is 4180 J.

Heat absorption:

Given information in the question:

Mass of water = M = 100g

Waters specific heat capacity C = (4.18)

ΔT = The temperature change of the reaction = 10°

Find:

Amount of heat absorbed by ice cube

Computation:

ΔH = 100 x 4.18 x 10

ΔH  = 4180J or 41.8KJ

so, the cube absorbed 4180J of energy

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