Ans: 14.9 m
The height from which the ball is dropped = 20 m
Velocity of the ball the = 10 m/s
Kinetic energy, KE = 1/2mv²
Potential energy, PE = mgh
The height at which KE = PE is
1/2mv² = mgh
v² = 2gh
h = v²/2g = (10)²/2(9.8) = 5.1 m
Height from the ground = 20-5.1 = 14.9 m