The concentration of hydronium ion, [H₃O⁺] = 1.3 × 10⁻⁶ M
Explanation:
HClO is a weak acid and it can be ionized and given by the equation as,
HClO + H₂O ⇄ H₃O⁺ + ClO⁻
Ka is given by the expression that the product of the concentration of products divided by the product of the concentration of the reactants.
[tex]$ Ka = \frac{[H_{3} O^{+}]\times [ClO^{-} ]}{[HClO]}[/tex] = 2.9 ×10⁻⁸
Consider [H₃O⁺] = [ClO⁻] = x
[HClO] = 0.365 - x
Since Ka is very small, consider x <<<0.365, also it should be ignored.
Ka = 2.9 ×10⁻⁸ = [tex]$\frac{x^{2} }{0.365}\\[/tex]
x² = 2.9 × 10⁻⁸ × 0.365
x = 1.3 × 10⁻⁶ M
Thus we can conclude 3rd Option as correct answer