Question

Calculate the energy released when a 28.9 gram piece of paper is cooled from its melting point of 1083 degrees Celsius to 25.0 degrees Celsius. The specific heat of copper is .385 j/g Celsius.

Answer 1

use equation: ΔH = MCΔT

M = mass of copper
C = specific heat capacity of copper 
ΔT = temp. change

ΔH = 28.9 x 385 x 3.9 =43393.35J or 43.39KJ

Answer 2

Answer : The energy released will be, -11771.837 J

Solution :

Formula used :

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

where,

Q = heat released = ?

m = mass of copper = 28.9 g

c = specific heat of copper = $0.385J/g^oC$      

$\Delta T=\text{Change in temperature}$  

$T_{final}$ = final temperature = $25^oC$

$T_{initial}$ = initial temperature = $1083^oC$

Now put all the given values in the above formula, we get :

$Q=28.9g\times 0.385J/g^oC\times (25-1083)^oC$

$Q=-11771.837J$

Therefore, the energy released will be, -11771.837 J