Question

Help for this math problem asap

Answer 1

Given:

It is given that the lines AB and DE are parallel.

We need to determine the value of x.

Value of x:

Let us use the property of similar triangles.

Thus, using the similar triangles, the corresponding sides of the triangle is given by

$\frac{AB}{ED}=\frac{BC}{CD}$

Substituting AB = 10, ED = 6, BC = 14 and CD = x in the above expression, we get;

$\frac{10}{6}=\frac{14}{x}$

Cross multiplying, we have;

$10x=14\times 6$

$10x=84$

  $x=8.4$

Thus, the value of x is 8.4