lilcrooky15 lilcrooky15

02-04-2020
Chemistry

contestada

How many grams of lead(II) iodide are produced from 6.000 moles of NaI according to the balanced equation: Pb(NO3)2 + 2 NaI à 2 NaNO3 + PbI2

Respuesta :

drpelezo drpelezo

03-04-2020

Answer:

mass PbI₂ formed = 1383 grams

Explanation:

Pb(NO₃)₂ + 2NaI => 2NaNO₃ + PbI₂(s)

6 mol NaI => 1/2(6 mol) PbI₂ = 3 mol PbI₂ x 461.01 g/mol = 1383.03 grams ≅ 1383 grams (4 sig. figs.)

Answer Link

Otras preguntas

Solve for x Answer choices: 4 5 8 3 2

what is context of poster" We Can Do It!"?

Write an equation to represent each function. (image attached)

what is the measure of B?

what is the zeff of carbon

Simplify: (-2)^-3 a) 8 b) 1/8 c) -8 d) -1/8

Match each item to its description by selecting an object from each group. Not all the items will be used.

35. The car ... when we got there. 1 point a. were crashing b. has crashed c. had crashed d. will have crashed

Encouraging successful business ventures in other countries to carry American values and culture is called: A. International diplomacy B. Dollar diplomacy C. Mo

Jill can answer 50 math questions every 20 minutes.Complete the table using equivalent ratios.Minutes - Number of math questions 20 - 50 12 - ____ 36 - ____What