Question

What is the volume of 4.9 mol of an ideal gas
at a pressure of 3 atm and a temperature of
0◦ C? 1 liter = 0.001 m^3
and 1 atm = 101300 Pascals. Answer in units of L.

Answer 1

Answer:

Volume of the gas is given as

$V = 0.11 m^3$

Explanation:

As we know by ideal gas equation

$PV = nRT$

here we know that

n = 4.9 moles

R = 8.314 J/ mol K

T = 0 degree = 273 K

P = 1 atm = 101300 Pa

now we have

$101300 V = 4.9(8.314)(273)$

$V = 0.11 m^3$