Question

(sqrt(24x ^ 5 * y ^ 7))/((6x ^ 3 * y ^ 4) ^ (1/2))

Answer 1

Answer:$\frac{(24qrst^{5}+qrsty^{7})\sqrt{6x^{3}+y^{4} } }{6x^{3}+y^{4}}$

Step-by-step explanation:

First, I would reorder $(6x ^ 3 * y ^ 4) ^ (1/2)$ into $\sqrt {6x^{3}+yx^{4}$

then you would need to multiply the parentheses by qrst

$\frac{24qrstxx^{5}+qrstyx^{7} }{6x^{3}+yx^{4}}$

Then multiply the fractions

$\frac{24qrst^{5}+qrsty^{7} }{6x^{3}+y^{4}}$  x  $\frac{6x^{3}+y^{4} }{6x^{3} + y^{4} }$

You should then have something that looks like this

$\frac{(24qrst^{5}+qrsty^{7})\sqrt{6x^{3}+y^{4} } }{\sqrt}6x^{3}+y^{4 }{\sqrt}6x^{3}+y^{4 }$

Then that's basically the answer