Answer:
1.63 kilo Joules of energy will be produced when 14.8 g of silver nitrate react.
Explanation:
[tex]AgNO_3+Ca\rightarrow Ag+CaNO_3,\Delta H_{rxn}=-18.7 kJ/mol [/tex]
Mass of silver nitrate = 14.8 g
Moles of silver nitrate = [tex]\frac{14.8 g}{170 g/mol}=0.08706 mol[/tex]
According to reaction, when 1 mole of silver nitrate reacts with 1 mole of calcium it gives 18.7 kJ of heat.
Then amount of heat released when 0.08706 moles of silver nitrate reacts :
[tex]0.08706\times 18.7 kJ=1.628 kJ\approx 1.63 kJ[/tex]
1.63 kilo Joules of energy will be produced when 14.8 g of silver nitrate react.