Question

A car weighing 1500 kg drives at 5m /s when it collides with a wall. It takes 0.20 seconds until the car is completely stationary. The driver weighs 90 kg. How much average force is the driver under the crash?

Answer 1

Answer:

2250 N

Explanation:

Assuming the driver decelerates at the same rate as the car:

a = (0 m/s − 5 m/s) / (0.20 s)

a = -25 m/s²

F = ma

F = (90 kg) (-25 m/s²)

F = -2250 N

The magnitude of the average force on the driver is 2250 N.