Without the figure we can't tell which angle A is. We'll write it both ways; you'll have to match the appropriate one to your problem.
If A is the angle opposite 17 then its the right angle. They're probably not giving us that problem.
If A is the angle opposite 15 then
[tex]\cos A = \dfrac{8}{17}[/tex]
[tex]\sin A = \dfrac{15}{17}[/tex]
[tex]\tan A = \dfrac{15}{8}[/tex]
If A's the one opposite 7 then cosine and sine swap and tangent gets flipped:
[tex]\cos A = \dfrac{15}{17}[/tex]
[tex]\sin A = \dfrac{8}{17}[/tex]
[tex]\tan A = \dfrac{8}{15}[/tex]