Question

a wire is bent into the shape of a square, each side is 5 in long. then the wire is now bent to the shape of a rectangle if the length of the rectangle is 6 in what is the width?

Answer 1

Answer:

Width of the rectangle= $4\,inches$

Step-by-step explanation:

The wire is bent from square to rectangle shape:

Therefore, Perimeter of the square= Perimeter of the rectangle

Perimeter of the square with side = 5 inch

Perimeter of a square = $4\times Side$

$=4\times 5\\\\=20\,inches$

Perimeter of the rectangle is also: $20\,inches$

Perimeter of a rectangle :

            $2(Length+Width)$

For, $Length=6\,inch$

       $Width=?$

$20=2(6+Width)\\\\\dfrac{20}{2} =6+Width\\\\10=6+Width\\\\Width=10-6\\\\Width=4 \,inches$

The width of the rectangle is : $4\,inches$