Answer:
CH4 + 2O2 -> CO2 + 2H2O
Explanation:
This reaction involves the combustion of methane (CH4)
General form of balancing reactions involving combustion of hydrocarbons is
CxHy + [x+(y/4)]O2 -> xCO2 + (y/2)H2O
x= the number of carbon atoms in the compound = 1
y= the number of hydrogen atoms in the compound = 4
CH4 + [(1+(4/4)]O2 -> CO2 + (4/2)H20
CH4 + (1+1)O2 -> CO2 + 2H2O
CH4 + 2O2 -> CO2 + 2H2O
Answer:
CH4 + 2O2 —> CO2 + 2H2O
Explanation:
CH4 + O2 —> CO2 + H2O
The above equation can be balance as follow:
Therefore are 4 atoms of H on the left side of the equation and 2 atoms on the right side. It can be balance by putting 2 in front of H2O as shown below:
CH4 + O2 —> CO2 + 2H2O
Now, there are a total of 4 atoms of O on the right side and 2 atoms on the left. It can be balance by putting 2 in front of O2 as shown below:
CH4 + 2O2 —> CO2 + 2H2O
Now, we can see that the equation is balanced as there are equal numbers of atoms of the different elements present on both sides of the equation.
