Question

(6 8 25 ÷(−1)−(−0.8)·(−0.1))÷(−0.25÷1.25−1 3 5 ÷(−5 1 3 ))

Answer 1

$\left(6 \dfrac{8}{25}\div (-1)-(-0.8)\cdot (-0.1)\right)\div\left (-0.25\div 1.25-1 \dfrac{3}{5} \div\left(-5 \dfrac{1}{3} \right)\right)=-64$

Step-by-step explanation:

Given : Expression $\left(6 \dfrac{8}{25}\div (-1)-(-0.8)\cdot (-0.1)\right)\div\left (-0.25\div 1.25-1 \dfrac{3}{5} \div\left(-5 \dfrac{1}{3} \right)\right)$

To find : Simplify the expression ?

Solution :

First we solve all multiplications and divisions individually,

$6\dfrac{8}{25}\div (-1)=-6\dfrac{8}{25}=-\dfrac{158}{25}=-6.32$

$(-0.8)\cdot (-0.1)=0.08$

$-0.25\div 1.25=-\dfrac{0.25}{1.25}=-\dfrac{25}{125}=-\dfrac{1}{5}=-0.2$

$1\dfrac{3}{5}\div \left(-5\dfrac{1}{3}\right)=-\dfrac{8}{5}\cdot \dfrac{3}{16}=-\dfrac{3}{10}=-0.3$

Substitute all the values,

$=-6.32-0.08\div(-0.2-(-0.3)$

$=-6.4\div 0.1$

$=-\dfrac{6.4}{0.1}$

$=-64$

Therefore, $\left(6 \dfrac{8}{25}\div (-1)-(-0.8)\cdot (-0.1)\right)\div\left (-0.25\div 1.25-1 \dfrac{3}{5} \div\left(-5 \dfrac{1}{3} \right)\right)=-64$