Question

The proof for the product property of logarithms requires simplifying the expression logb(bx+y) to x + y. Which property is used to justify this step?

Answer 1

Answer:

$log_bb^c=c$

Step-by-step explanation:

We are given that

$log_bb^{x+y}=x+y$

We have to find the property which is used to justify this step.

We know that

$e^{x+y}=e^x\cdot e^y}$

Using the formula

$log_b(b^x\cdot b^y)}=log_bb^x+log_bb^y$

By using the formula

$log(m\cdot n)=log m+log n$

$log_bb^{x+y}=x+y$

By using the property

$log_bb^c=c$

Answer 2

Answer:

c. on edge

Step-by-step explanation: