Question

A 970 kg car starts from rest on a horizontal roadway and accelerates eastward
for 5 s when it reaches a speed of 25 m/s. What is the average force exerted on
the car during this time? (Hint: Find acceleration of the car, then use the equation
F=ma.)

Answer 1

Answer: 4850N

Explanation:

Mass of car = 970 kg

Time = 5 s

Speed = 25 m/s

Average force exerted on the car = ?

Recall that Force is the product of the mass of an object and the acceleration by which it moves

i.e Force = mass x acceleration

(Since, acceleration is the rate of change of velocity or speed per unit time)

i.e Acceleration = Speed / Time

Acc = 25m/s / 5s

Acc = 5m/s^2

Average force = mass x acceleration

Avg force = 970 kg x 5m/s^2

= 4850N

Thus, the average force exerted on the car is 4850 Newton

Answer 2

The average force exerted on the car during this time will be "4850 N". To understand the calculation, check below.

Force and Mass

According to the question,

Time, t = 5 s

Speed, v = 25 m/s

We know the relation,

→ Acceleration = $\frac{Speed}{Time}$

By substituting the values,

                         = $\frac{25}{5}$

                         = 5 m/s²

hence,

→ Force = Mass × Acceleration

             = 970 × 5

             = 4850 N

Thus the above answer is correct.

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