Question

Suppose a city with population of 800,000 has been growing at a rate of 4​% per year. If this rate​ continues, find the population of this city in 10 years.

Answer 1

Answer:

The population of this city in 10 years is 118,4160.

Step-by-step explanation:

Given:

Suppose a city with population of 800,000 has been growing at a rate of 4​% per year.

If this rate​ continues.

Now, to find the population of this city in 10 years.

Let the population after growth be $A.$

Original population ($P$) = 800,000.

Growing rate per year ($r$) = 4%.

Number of years ($t$) = 10 years.

Now, we put formula to get the population of the city in 10 years:

$A=P(1+r)^t$

$A=800,000(1+4\%)^{10}$

$A=800,000(1+0.04)^{10}\\\\A=800,000(1.04)^{10}\\\\A=800,000\times 1.4802\\\\A=118,4160.$

Therefore, the population of this city in 10 years is 118,4160.