Question

5. By approximately what factor would the mass of a sample of copper-66
decrease in 51 minutes? The half-life of copper-66 is 5.10 minutes.

Answer 1

that’s picture right there should help u with your works

Answer 2

The factor would be "$\frac{1}{1024}$".

According to the question,

• $51 \ minutes = 10 \frac{1}{2} \ lifes$

Copper's half life,

• 5.10 minutes

Now,

The factor would the mass of a sample of copper-66  decrease in 51 minutes would be:

→ $\frac{5.10}{51} = 10$

then,

→ $(\frac{1}{2})^{10} = \frac{1}{1024}$

Thus the answer above is right.

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