Answer: He should include 720 hard drives in his new sample.
Step-by-step explanation:
Let E be the margin of error and n be the sample size , then 4
[tex]E\ \alpha\ \dfrac{1}{\sqrt{n}}[/tex]
Also, by equation of inverse variation , we have
[tex]E_1\sqrt{n_1}=E_2\sqrt{n_2}[/tex]
Put [tex]n_1=45,\ E_1=20 , E_2=5[/tex] (given) , we get
[tex]20\sqrt{45}=5\sqrt{n_2}\\\\\Rightarrow\ \sqrt{n_2}=4\sqrt{45}[/tex]
Taking square on both sides , we get
[tex]n_2=(4\sqrt{45})^2=4^2\times45=720[/tex]
Hence, he should include 720 hard drives in his new sample.