Question

On January 21 in 1918, Granville, North Dakota, had a surprising change in temperature. Within 12 hours, the temperature changed from 237 K to 283 K. What is this change in temperature in the Celsius and Fahrenheit scales?

Answer 1

Answer: The change in temperature is -269.17°C and -452.51°F.

Step-by-step explanation:

Since we have given that

Initial temperature = 237 K

Within 12 hours,

Temperature becomes 283 K

So, Change of temperature would be

$\dfrac{283-237}{12}=3.83\ K$

So, in Celsius Scales would be

$T_C=(T-273)^\circ C=(3.83-273)^\circ C=-269.17^\circ C$

In Fahrenheit scales, it would be

$T_F=\dfrac{9}{5}T_C+32\\\\T_F=\dfrac{9\times -269.17}{5}+32\\\\T_F=-484.506+32\\\\T_F=-452.51^\circ F$

Hence, the change in temperature is -269.17°C and -452.51°F.

Answer 2

The change in temperature in the Celsius and Fahrenheit scales are -36 degree Celsius to 10 degree Celsius and -32.8 degree Fahrenheit to 50  degree Fahrenheit

The initial and the final temperatures in degree Kelvin are given as:

237K and 283K

To convert the above temperatures to degree Celsius, we have:

$^oC = K - 273$

So, we have:

$^oC_1 = 237 - 273$

$^oC_1 = -36$

$^oC_2 = 283 -273$

$^oC_2 = 10$

Next, we convert the temperatures to degree Fahrenheit using

$F = C \times 1.8 + 32$

So, we have:

$F_1 = -36 \times 1.8 + 32$

$F_1 = -32.8$

$F_2 = 10 \times 1.8+32$

$F_2 = 50$

Hence, the change in temperature in the Celsius and Fahrenheit scales are -36 degree Celsius to 10 degree Celsius and -32.8 degree Fahrenheit to 50  degree Fahrenheit

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