Question

(using the formula given in the lesson, solve the following problem.)
the specific heat of water is 1.00 cal/g °c. if 10 g of water were heated and the water changed by 50°c, how many calories of heat energy would be absorbed by the water?
____ calories
500
50
10

Answer 1

The heat absorbed can be calculate using the equation:

$Q = m\cdot c_e\cdot \Delta T$

$Q = 10\ g\cdot 1\frac{cal}{g\cdot ^\circ C}\cdot 50\ ^\circ C = \bf 500\ cal$