Question

A 214 kg boat is sinking in the ocean. The force of gravity that draws the boat down is partially offset by the buoyant force of the water, so that the net unbalanced force on the boat is 1310 N. What is the acceleration of the boat?

Answer 1

Answer:

$3.68 m/s^2$

Explanation:

We are given that

Mass of boat=m=214 kg

F=1310 N

We have to find the acceleration of the boat.

Net force=mg-F=mg-1310

Where $g=9.8 m/s^2$

$F_{net}=214\times 9.8-1310=787.2 N$

We know that

Acceleration ,a$=\frac{F_{net}}{m}$

Using the formula

$a=\frac{787.2}{214}=3.68 m/s^2$

Hence, the acceleration of the boat=$3.68 m/s^2$

Answer 2

The  acceleration of the boat is 3.678 m/s^2.

• The calculation is as follows:

The net force is

= mg - 1310

= 214(9.8) - 1310

= 787.2 N

Now the acceleration is

$= 787.2N\div 214$

= 3.678 m/s^2

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