Question

At a certain location, the earth's magnetic field has a magnitude of 5.7×10−5 t and points in a direction that is 73 ∘ below the horizontal. part a find the magnitude of the magnetic flux through the top of a desk at this location that measures 81 cm by 85 cm

Answer 1

Answer:

1.15 * 10^(-5) Tm²

Explanation:

Parameters given:

Magnitude of magnetic field, B = 5.7 * 10^(-5) T

Angle of magnetic field to the horizontal plane = 73°

Dimension of the desk = 81 cm × 85 cm

Area of desk, A = 6885 cm² = 0.6885 m²

The magnitude of the Magnetic Flux, |Φ|, is given as:

|Φ| = |B * A * cosθ|

Where θ = angle of the Magnetic field to the normal of the desk = 90 - 73 = 17°

Therefore, the magnitude of the Magnetic Flux will be:

|Φ| = |5.7 * 10^(-5) * 0.6885 * cos17|

|Φ| = 3.75 * 10^(-5) Tm²

Answer 2

When the magnitude of the magnetic flux through the top of a desk at this location is = $1.15 * 10\wedge (-5) Tm2$

Calculate of Parameters

Parameters as per the question given:

Then The Magnitude of the magnetic field, $B = 5.7 * 10\wedge (-5) T$

Then, The Angle of the magnetic field to the horizontal plane = 73°

After that, The Dimension of the desk = is 81 cm × 85 cm

Now, The Area of desk, A = 6885 cm² = 0.6885 m²

When The magnitude of the Magnetic Flux, |Φ|, is given as:

Then, |Φ| = |B * A * cosθ|

Where θ is = angle of the Magnetic field to the normal of the desk = 90 - 73 = 17°

Thus, the magnitude of the Magnetic Flux will be:

|Φ| =$|5.7 * 10\wedge (-5) * 0.6885 * cos17|$

|Φ| =$3.75 * 10\wedge (-5) Tm²$

Find more information about Parameters here:

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