Answer:
Power of the source is 7.7 W
Explanation:
As we know that the sound level is measured as
[tex]L = 10 Log \frac{I}{I_o}[/tex]
now we have
[tex]L = 109.0 dB[/tex]
so we have
[tex]109.9 = 10 Log\frac{I}{10^{-12}}[/tex]
[tex]I = 0.098 W/m^2[/tex]
now power of the source is given as
[tex]P = I(4\pi r^2)[/tex]
[tex]P = 0.098(4\pi )(2.5^2)[/tex]
[tex]P = 7.7 W[/tex]