Answer:
- 12.5 °C to 52.5 °C
Explanation:
Let the initial resistance is Ro and the initial temperature is To = 20°C.
temperature coefficient of resistance, α = 0.0004 /°C
Case I : For maximum resistance:
Maximum resistance, R' = Ro + 1.30 % of Ro
[tex]R' = R_{0}\left ( 1+\frac{1.3}{100} \right )=1.013 R_{0}[/tex]
let the temperature difference is ΔT.
R' = Ro (1 + αΔT)
1.013 Ro = Ro ( 1 + 0.0004 ΔT)
ΔT = 32.5 °C
So, the maximum value of resistance is
T = 32.5 + 20 = 52.5 °C
Case II: For minimum value of resistance :
Minimum resistance, R'' = Ro - 1.30 % of Ro
[tex]R'' = R_{0}\left ( 1-\frac{1.3}{100} \right )=0.987 R_{0}[/tex]
let the temperature difference is ΔT.
R'' = Ro (1 + αΔT')
0.987 Ro = Ro ( 1 + 0.0004 ΔT')
ΔT' = - 32.5 °C
So, the maximum value of resistance is
T' = - 32.5 + 20 = - 12.5 °C
So, the range of temperature is - 12.5 °C to 52.5 °C.