Question

how would i do this surface area problem? picture is included

Answer 1

Answer:

$SA=210cm^2$

Step-by-step explanation:

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1. Find area of triangle.

$A=\frac{1}{2} bh$

$A=\frac{1}{2}(6)(9.9)$

$A=\frac{1}{2}(59.4)$

$A=29.7$

2. Identify how many triangles are there.

There are 5 triangles.

3. Find area of total triangles.

$A=29.7(5)$

$A=148.5$

4. Find area of pentagon.

$A=5(\frac{1}{2}bh)$

$A=5[\frac{1}{2}(6)(4.1)]$

$A=5[\frac{1}{2}(24.6)]$

$A=5(12.3)$

$A=61.5$

5. Add area of total triangles and area of pentagon.

$SA=148.5+61.5$

$SA=210$