Question

Temperature measurements are converted between degrees Fahrenheit (F) and degrees Celsius (C) by the following formula.



The temperature in Dallas rose from the morning temperature of 46°F to the afternoon high of 72°F. What was the difference in temperature in degrees Celsius, to the nearest degree?

Answer 1

Answer:

14°C

Step-by-step explanation:

(°F − 32) × 5/9 = °C

(46°F − 32) × 5/9 = 7.778°C  which is about 8°C

(72°F − 32) × 5/9 = 22.222°C  which is about 22°C

22°C  - 8°C  = 14°C

Answer 2

The difference in temperature from morning to evening is $14$ °Celsius.

$(F-32)\times \frac{5}{9} = C$

Change the morning and evening temperature from F to C.

$46 \degree F$  

$(F-32)\times \frac{5}{9} = C$

$(46-32)\times \frac{5}{9} = C$

$14 \times \frac{5}{9} = C$

$7.78 =C$

$72 \degree F$  

$(F-32)\times \frac{5}{9} = C$

$(72-32)\times \frac{5}{9} = C$

$40 \times \frac{5}{9} = C$

$22.22 =C$

The temperature in morning in degrees Celsius, to the nearest degree is

$8$°C.

The temperature in evening in degrees Celsius, to the nearest degree is

$22$ ° C.

So, difference in temperature from morning to evening is $14$ ° Celsius.

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