Question

what is the quotient (x3 8) ÷ (x 2)?



x2 2x 4

x2 – 2x 4

x2 4

x2 – 4

Answer 1

If you would like to solve (x^3 + 8) / (x + 2), you can do this using the following steps:

x^3 + 8 = (x + 2) * (x^2 - 2x + 4)

(x^3 + 8) / (x + 2) = (x + 2) * (x^2 - 2x + 4) / (x + 2) = x^2 - 2x + 4

The correct result would be x^2 - 2x + 4.

Answer 2

As the Question is not clear

But there are two possibilities

1. $\frac{x^3+8}{x+2}=\frac{(x+2)(x^2-2 x+4)}{x+2}=x^2-2 x+4$→→Cancelling x+2 from numerator and denominator

→→ Using the formula (a³ + b³) =(a+b)(a² - ab + b²)

Or if

$\frac{x^3-8}{x-2}=\frac{(x-2)(x^2+2x+4)}{x-2}=x^2+ 2 x +4$→→Cancelling x-2 from numerator and denominator

Using the formula (a³ - b³) =(a-b)(a² + ab + b²)

Statement (1) appears true.

So, correct option is  x²- 2 x + 4 or x² + 2 x + 4