Question

At Robin's Snow Cones, the shaved ice portion of the cone is shaped like a perfect sphere with a diameter of 8
cm. Exactly half of the shaved ice sphere extends above the paper cup holder. What is the volume of ice that
extends above the cup to the nearest cubic centimeter?
In your calculations, use 7 = 3.14
PLEASE HELPPPPP

Answer 1

Answer:

134 cubic centimeters

Step-by-step explanation:

The extended part is basically the volume of HALF A SPHERE.

First, the volume of full sphere is:

$V=\frac{4}{3}\pi r^3$

Hence, the half sphere volume would be:

$Half \ Sphere = \frac{\frac{4}{3}\pi r^3}{2}=\frac{2}{3}\pi r^3$

We know the diameter is 8, radius is HALF OF THAT, so

Radius = 8/2 = 4

Substituting, we find (remembering to use 3.14 as pi):

$\frac{2}{3}\pi r^3\\=\frac{2}{3}\pi (4)^3\\=\frac{2}{3}(3.14)(64)\\=133.97$

To the nearest cubic centimeter, the answer is:

134 cubic centimeters

Answer 2

The volume of ice that extends above the cup to the nearest cubic centimeter is 134 cubic cm.

What is the volume of hemisphere?

If the given sphere is of radius r units, then its half volume (or the volume of the hemisphere) is given as:

$V= \dfrac{2}{3} \pi r^3 \: \rm unit^3$

For this case, we're specified that:

Radius of the sphere from which hemisphere's volume is to be known = 8 cm

Thus, we get:

$\text{Volume of hemisphere} = V = \dfrac{2}{3} \pi r^3 \: \rm unit^3\\\\V = \dfrac{2}{3} \pi r^3 \approx \dfrac{2}{3} \times 3.14 \times (4)^3 \approx 134\: \rm cm^3$

Thus, the volume of ice that extends above the cup to the nearest cubic centimeter is 134 cubic cm.

Learn more about volume of hemisphere here:

https://brainly.com/question/13250046