Answer: The area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.
Step-by-step explanation:
I will assume that the exercise says "[tex]\frac{1}{3}[/tex] times the base and height of Jerry’s rhombus".
The area of a rhombus can be calculated with the following formula:
[tex]A=b*a[/tex]
Where "b" is the length of the base and "a" is the altitude or the height.
Then, you can calculate the area using the formula shown above.
Therefore, you get:
1. Jerry's rhombus:
[tex]A_1=(15\ in)(9\ in)\\\\A_1=135\ in^2[/tex]
2. Charlene's rhombus:
[tex]A_2=(\frac{1}{3}*15\ in)(\frac{1}{3}*9\ in)\\\\A_2=(5\ in)(3\ in)\\\\A_2=15\ in^2[/tex]
Dividing the area calculated, you get:
[tex]\frac{135\ in^2}{15\ in^2}=9[/tex]
Therefore, you can conclude that the area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.