Answer:
C₂ = 0.334 M
Explanation:
Given data:
Volume of HCl = 0.0780 L
Concentration of HCl = 0.12 M
Volume of LiOH = 0.0280 L
Concentration of LiOH = ?
Solution:
Formula:
C₁V₁ = C₂V₂
C₁ = Concentration of HCl
V₁ = Volume of HCl
C₂ = Concentration of LiOH
V₂ = Volume of LiOH
Now we will put the values in formula.
C₁V₁ = C₂V₂
0.12 M × 0.0780 L = C₂ × 0.0280 L
0.00936 M.L = C₂ × 0.0280 L
C₂ = 0.00936 M.L/0.0280 L
C₂ = 0.334 M