Respuesta :
Answer:
a) Null hypothesis H₀ : There is no difference between rental rates of Hong Kong and Paris.
Alternative hypothesis H₁:
The rental rates is higher in Hong Kong than in Paris
That is H₁ :x₁⁻ > x₂⁻
b) By tabulated value z = 2.58 at 0.01 level of significance
c) the null hypothesis is accepted.
Rental rates are not higher in Hong Kong than in Paris?
Step-by-step explanation:
Step 1:-
Annual lease rates for a sample of 30 commercial properties
size of the sample n₁ = 30
Given data in Hong Kong Annual lease rates of showed an average of $1114 per square meter with a standard deviation of $230.
sample mean x₁⁻ = $1114
sample standard deviation σ₁ = 230
Given data Annual lease rates for a sample of 40 commercial properties in Paris showed an average lease rate of $989 per square meter with a standard deviation of $195.
Size of second sample n₂ =40
mean of the second sample x₂⁻ = $989 per square meter
sample standard deviation σ₂ = 195
Step 2:-
Null hypothesis H₀ : There is no difference between rental rates of Hong Kong and Paris.
Alternative hypothesis H₁:
The rental rates is higher in Hong Kong than in Paris
That is H₁ :x₁⁻ > x₂⁻
Level of significance:α = 0.01
Step 3:-
The test statistic Z = [tex]\frac{x^{-} _{1}-x^{-} _{2} }{\sqrt{\frac{ σ₁^2}{n_{1} }+\frac{ σ^2_{2} }{n_{2} } } }[/tex]
now substitute values σ₁ = 230 , σ₂ = 195 , n₁ = 30 and n₂ =40
Z = 2.39
on calculation we get Z = 2.39
By tabulated value z = 2.58 at 0.01 level of significance
Z = 2.39< 2.58
Therefore the null hypothesis is accepted.
Rental rates are not higher in Hong Kong than in Paris?
Final answer :-
a) Null hypothesis H₀ : There is no difference between rental rates of Hong Kong and Paris.
Alternative hypothesis H₁:
The rental rates is higher in Hong Kong than in Paris
That is H₁ :x₁⁻ > x₂⁻
b) By tabulated value z = 2.58 at 0.01 level of significance
c) the null hypothesis is accepted.
Rental rates are not higher in Hong Kong than in Paris?
