Answer:
The final volume of the balloon is = 28.11 L
Explanation:
Initial pressure [tex]P_{1}[/tex] = 1.03 atm = 104.325 K pa
Initial temperature [tex]T_{1}[/tex] = 26 °c = 299 K
Initial volume [tex]V_{1}[/tex] = 22.4 L
Final temperature [tex]T_{2}[/tex] = 22 °c = 295 K
Final pressure [tex]P_{2}[/tex] = 0.81 atm = 82 K pa
We know that
[tex]\frac{P_{1} V_{1} }{T_{1} } = \frac{P_{2} V_{2} }{T_{2} }[/tex]
Put all the values in above formula we get
[tex]\frac{(104.325)(22.4)}{299} = \frac{(82)(V_{2} )}{295}[/tex]
[tex]V_{2}[/tex] = 28.11 L
This is the final volume of the balloon.