Question

Twenty-one people are to be divided into two teams, the Red Team and the Blue Team. There will be 10 people on Red Team and 11 people on Blue Team. In how many ways can this be done?

Answer 1

Answer:

352710

Step-by-step explanation:

total number of persons = 21

number of members in red team = 10

number of members in blue team = 11

As we select 10 persons for red team, the rest of the members are in the blue team.

The ways to select 10 persons out of 21

= $^{21}C_{10}=\frac{21!}{10!\times 11!}=352710$

Thus, the number of ways to select the 10 members for red team and 11 members for blue team are 352710.