An oil slick is expanding as a circle. The radius of the circle is currently 2.5 inches and is increasing at a rate of 6.5 inches per hour. Express the area of the circle, A as a function of h, the number of hours elapsed.

Respuesta :

Answer:

[tex] A = \pi r^2[/tex]

So we can express the radius in terms of the hours elapsed like this:

[tex] r = 2.5 + 6.5 h[/tex]

And the reason of this is because each hour the radius increase 6.5 inches, and if we replace in the formula of area we got:

[tex] A = \pi (2.5 +6.5 h)^2 [/tex]

And this function would represent the area of the circle as function of the hours elapsed, [tex] h\geq 0[/tex]

Step-by-step explanation:

For this case we know the radius of a circle given [tex] r = 2.5 in[/tex] and we also know the incresing rate for the radius:

[tex] \frac{dr}{dt}= 6.5 \frac{inches}{\hour}[/tex]

And we want to express the are of the circle A as a function of h = the number of hours elapsed.

We know that the area of a circle is given by:

[tex] A = \pi r^2[/tex]

So we can express the radius in terms of the hours elapsed like this:

[tex] r = 2.5 + 6.5 h[/tex]

And the reason of this is because each hour the radius increase 6.5 inches, and if we replace in the formula of area we got:

[tex] A = \pi (2.5 +6.5 h)^2 [/tex]

And this function would represent the area of the circle as function of the hours elapsed, [tex] h\geq 0[/tex]