Respuesta :

The answer for the following question is mentioned below.

[tex]N_{2}H_{4}[/tex] +3 [tex]O_{2}[/tex] →2 [tex]NO_{2}[/tex] +2 [tex]H_{2} O[/tex]

the equation is balanced.

Explanation:

The steps required to balance a chemical equation is:

Firstly,write the formula of the compound/substance.

Secondly,count the number of atoms in each element on each side of the equation

Thirdly,Adjust the co-efficient.Balance the atoms or the ions present in the greatest number.

You may do this by finding the lowest common multiple of two.

Continue systematically to balance the atoms or ions on the rest of the side (i.e.)on the other side.

Lastly,check the number of atoms each elements is same on both the sides

From the equation:

Before balancing the equation:

[tex]N_{2} H_{4}[/tex] + [tex]O_{2}[/tex] → [tex]NO_{2}[/tex] + [tex]H_{2} O[/tex]

After balancing the equation:

[tex]N_{2}H_{4}[/tex] +3 [tex]O_{2}[/tex] →2 [tex]NO_{2}[/tex] +2 [tex]H_{2} O[/tex]

Therefore the given equation is balanced.

Hey there!

N₂H₄ + O₂ → NO₂ + H₂O

Balance N.

2 on the left, 1 on the right. Add a coefficient of 2 in front of NO₂.

N₂H₄ + O₂ → 2NO₂ + H₂O

Balance H.

4 on the right, 2 on the right. Add a coefficient of 2 in front of H₂O.

N₂H₄ + O₂ → 2NO₂ + 2H₂O

Balance O.

2 on the left, 6 on the right. Add a coefficient of 3 in front of O₂.

N₂H₄ + 3O₂ → 2NO₂ + 2H₂O

Our final equation: N₂H₄ + 3O₂ → 2NO₂ + 2H₂O

Hope this helps!