Question

F(x) = -4x^2+10x-8f(x)=−4x 2 +10x−8f, left parenthesis, x, right parenthesis, equals, minus, 4, x, squared, plus, 10, x, minus, 8 What is the value of the discriminant of fff? How many distinct real number zeros does fff have?

Answer 1

Answer:

The value of Discriminant is -28.

The discriminant is negative, it implies that the function has no real solution.

Step-by-step explanation:

Given,

$f(x)=-4x^2+10x-8$

We need to find the value of discriminant.

And also we need to find the number of real zeros 'f(x)' have.

Solution,

We have given the quadratic equation;

$f(x)=-4x^2+10x-8$

where  

 $a = -4\\\\b = 10\\\\c = -8$

Now we will find the Discriminant.

Discriminant can be calculated by using the formula $b^2 - 4ac$.

Substituting the values we get;

$D=b^2 - 4ac = 10^2-4\times(-4)\times(-8)=100-128 =-28$

Hence the value of Discriminant is -28.

Since the discriminant is negative, it implies that the function has no real solution.

Answer 2

Answer:

the discriminant of f is −28

f has 0 distinct real number zeros.

Step-by-step explanation:

trust me bro

got it from Khan