Question

Which polynomial function has a leading coefficient of 1 and roots 21 and 31 with multiplicity 1?

f(x) = (x - 2)(x – 31)

f(x) = (x + 21)(x + 3)

f(x) = (x - 2)(x − 3)(x - 2)(x – 31)

fix) = (x + 2y + 211

Answer 1

Answer:

Which i think is the first one, there may just be a typing error.

Step-by-step explanation:

A polynomial of order n has the following format:

$f(x) = a(x - x_{0})(x - x_{1})...(x - x_{n-1})$

In which a is the leading coefficient, $x_{0}, x_{1},..., x_{n-1}$ are the roots.

If a root appears m times, they are said to have multiplicity m.

Leading coefficient of 1 and roots 21 and 31 with multiplicity 1

$f(x) = 1(x - 21)(x - 31)$

So the correct answer is:

$f(x) = 1(x - 21)(x - 31)$

Which i think is the first one, there may just be a typing error.